Perhatikanlah komponen tangensial gaya berat adalah $F_g=-mg sin \theta$ Untuk gerak melingkar dengan pusat P berlaku $\tau=I\alpha $ $-mgl sin \theta = ml^2\frac{\mathrm{d^2} \theta}{\mathrm{d} t^2}$ $\frac{\mathrm{d^2} \theta}{\mathrm{d} t^2}=-\frac{g}{l} sin\theta$
$$\frac{d\mathbf{v}}{dt} = q (\mathbf{E} + \mathbf{v} \times \vec{B})$$ $$\style{font-family:Arial}{dt}$$
$$\gamma \equiv \frac{1}{\sqrt{1- {\beta}^2}}$$
$$\begin{bmatrix} 5 & 8 \\ 2 & 3 \end{bmatrix}$$
\(ax^2 + bx + c = 0\) $$x = {-b \pm \sqrt{b^2-4ac} \over 2a} $$
$$ \vec{\nabla} \times \vec{F} = \left( \frac{\partial F_z}{\partial y} - \frac{\partial F_y}{\partial z} \right) \mathbf{i} + \left( \frac{\partial F_x}{\partial z} - \frac{\partial F_z}{\partial x} \right) \mathbf{j} + \left( \frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y} \right) \mathbf{k} $$